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When you have something like "infinity," you have to realize that it's not a number. Perhaps you meant the indeterminate form ##[1^\infty]## (written in brackets to emphasize that this is an indeterminate form). In these cases, a particular operation can be performed to solve each of the indeterminate forms. It’s just the reciprocal of [math]1^\infty[/math] which is an indeterminate form. $\endgroup$ – user3680 Oct 9 '13 at 23:42 $\begingroup$ All the answers here assume $0^{\infty}$ is $0^{+\infty}$. $\begingroup$ If we type those expressions into Mathematica, however, it tells us that 0^infinity is 0 and 1^infinity is indeterminate. I know regular numbers like 1/infinity = 0. Thanks, anything would help. Indeterminate Form 1. And could u tell me all the indeterminate forms like 0/0, infinity/infinity,...ect. This is one example of indeterminate forms. If you ask me, i would disagree with people saying that this is an indeterminate form or an undefined number! Other similar examples are $\infty^0$ and $0*\infty$, which are also undefined. Yes, [math]1^{-\infty}[/math] is an indeterminate form. This limit -- ##\lim_{n \to \infty}(1 + \frac 1 n)^n## -- is an example of this indeterminate form. Show us, how exactly do you proceed to carry out the multiplication, and what are the digits of your number 'infinity'? So is the answer just 0. Naively, you might think that since the quantity in parentheses is approaching 1 as the exponent increases without bound, the value of the limit is just 1. I think i am over thinking this question and answer is just 0 right. What is 1^infinity? Infinity over Infinity… Indeterminate Forms An indeterminate form does not mean that the limit is non-existent or cannot be determined, but rather that the properties of its limits are not valid. But Wikipedia doesn't assume that. 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